PPT Slide

If we concatenate C1 = [n1, k1, d1]q1 with C2 = [n2, k2, d2]q2 we get a C1 ? C2 = [n1n2, k1k2, d’]q2 code, where d’ ? d1d2.

Reed Solomon Code:

[n, k, n - k]q in general.

Let’s say n = q = 2m , and k = 0.4n. So we have [n, .4n, .6n]2m

Hadamard Code:

[2L , L , 2L-1]2 in general.

Let L = m, so we get

[2M , M , 2M-1]2 =

[n , lg(n) , n/2]2

With their powers combined we get [n2 , .4n lg(n) , .3n2]2 !